import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;

/**
 * More issues with exception handling
 * 
 * @author gtowell Created: Feb 11, 2020
 */
public class CatchErr4 {
    /**
     * better exception handling. The issue here is that the try still covers too
     * much ground 1. There are two completely different exceptions in two different
     * places by inner try 2. If dividebyzero can never get out of it!
     * 
     * @param args Unused.
     */
    public static void main(String[] args) {
        BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
        int prev = 10;
        while (prev >= 0) {
            try {
                System.out.print("Enter a number: ");
                String line = br.readLine();
                try {
                    int data = Integer.parseInt(line);
                    System.out.println(data + " / " + prev + " = " + (data / prev));
                    prev = data;
                } catch (NumberFormatException e) {
                    System.err.println("That's not a number!");
                } catch (ArithmeticException ae) {
                    System.err.println("Division by Zero" + ae);
                }

            } catch (IOException ioe) {
                System.err.println("Problem reading from keyboard" + ioe);
            }
        }
    }
}