/*
 * The Java definite assignment trap.
 * THIS CODE FAILS TO COMPILE.
 * Before a value can be used, Java requires that its value has been set.
 * So in  the main below "int bb..." fails because we are trying to set the value of
 * bb to something from aa -- which has not been set. The print does not compile
 * for similar reasons
 * 
 * @author gtowell
 * Created: Sep 2022
 */
public class Defin {
    public static void main(String[] args) {
        int j = 9;
        int aa;
        if (j==9) {
            aa = 6;
        }
        int bb = aa+5;
        System.out.format("%d %d\n", aa, bb);
    }
}